[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6700\\ P=\textit{original amount deposited}\dotfill & \$3600\\ r=rate\to 4.42\%\to \frac{4.42}{100}\dotfill &0.0442\\ t=years \end{cases} \\\\\\ 6700=3600[1+(0.0442)(t)]\implies \cfrac{6700}{3600}=1+0.0442t\implies \cfrac{67}{36}=1+0.0442t \\\\\\ \cfrac{67}{36}-1=0.0442t\implies \cfrac{31}{36}=0.0442t\implies \cfrac{\frac{31}{36}}{0.0442}=t\implies 19.5\approx t[/tex]
