help please and show work:)
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The height of the triangle will be equal to H=8.66 inches and the area of the triangle will be 43.30 square inches.
The space covered by the triangle in the two-dimensional plane will be the area of the triangle.
It is given that in the triangle all three sides are 10 inches:-
Height of the triangle=?
Area of the triangle=?
First the height of the triangle will be calculated as:-
[tex]\rm Tan\theta=\dfrac{P}{B} \\\\\\Tan\theta=\dfrac{P}{5}\\\\\\Tan60=\dfrac{P}{5}\\\\\\P=8.66\ inches[/tex]
The area of the triangle will be:-
[tex]\rm Area= \dfrac{1}{2}\times Base\times Height\\\\\\Area=\dfrac{1}{2}\times 5\times 8.66\\\\\\Area = \43.30\ square \ inches[/tex]
Hence the height of the triangle will be equal to H=8.66 inches and the area of the triangle will be 43.30 square inches.
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