Respuesta :

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

Number of Molecules in 2g of AlCl3

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

[tex]133.34g = 6.023*10^2^3[/tex]

If we equate this

[tex]133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules[/tex]

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

https://brainly.com/question/21150359

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