To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
The molar mass of AlCl3 is given as 133.34g/mol
Data;
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.
[tex]133.34g = 6.023*10^2^3[/tex]
If we equate this
[tex]133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules[/tex]
From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
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