Work out length of AB
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[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]
[tex] \large\underline{ \boxed{ \sf{✰\:Note }}}[/tex]
★ 1st let's know what is the given figure is and it's related concepts for solving !
➣ Given Triangle is a right angled triangle
➣ It is having 3sides let's know what are the name of these sides
➣ 1st AB is know as hypotenuse
➣ 2nd AC and is called Base of the triangle
➣ 3rd BC whích is know as perpendicular of the triangle
➣ Hypotenuse(H):-The side of a right triangle opposite the right angle.
➣ Perpendicular(P):- Exactly upright; extending in a straight line.
➣ Base(B):- it also known as the side opposite to hypotenuse
➣Perpendicular and base are know as the leg of right angled triangle
➣ We can easily find length of one missing side by using a theorem name as "Pythagorean theorem"
➣ Pythagorean theorem :- A mathematical theorem which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of those of the two other sides
★ Note :- The Pythagorean theorem only applies to right triangles.
[tex] \rule{70mm}{2.9pt}[/tex]
★ Writing this theorem mathematically ★
[tex] { \boxed{✫\underline{ \boxed{ \sf{Pythagorean \: theorem \: ⇒ {Hypotenuse }^2={ Base }^2+ {Height }^2}}}✫}}[/tex]
★ Here ★
➣ Base (AC)= 22cm
➣ Perpendicular (height) (BC)= 8cm
[tex] \rule{70mm}{2.9pt}[/tex]
✝ Assumption ✝
➣ let Hypotenuse ( AB ) = "x"
[tex] \boxed{ \rm{ \pink ➛AB^2= AC^2+BC^2}}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
✝ let's substitute values ✝
[tex]\rm{ \pink ➛x^2=22 ^2+8^2} \\ \rm{ \pink ➛x^2 = 484+ {64} } \\ \rm{ \pink ➛ {x}^{2} = 548 } \\ \rm{ \pink ➛= {x} = \sqrt{548} } \\ \rm{ \pink ➛ x = 2\sqrt{137} \: or23.4} \\ [/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
Hence Hypotenuse (AB) in the given triangle is of
[tex] { \boxed{✛\underline{ \boxed{ \sf{2\sqrt{137} \: or23.4\green✓}}}✛}}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
Hope it helps !