contestada

A camel hump contains 12 kg of triacyclglycerols,

a) Given that there are 0.491 moles of ATP per gram of fat, how many moles of ATP could be produced by the fat in the camel hump?
______moles

b) If the hydrolysis of ATP releases 7.3 kcal/mole, how many kilocalories are produced by the utilization of the fat?
______kcal

Respuesta :

The answer is 5892 moles of ATP will be produced from 12 kg of triacyclglycerols, and 43012 kcal energy will be generated by the utilization of the fat .

What are Triacyclglycerols ?

Triacylglycerols are formed by linking fatty acids with an ester linkage to three alcohol groups in glycerol.

Triacylglycerols are the form in which fat energy is stored in adipose tissue.

A camel hump contains 12kg = 12000 gm of Triacyclglycerols

a) It is given that there are 0.491 moles of ATP per gram of fat ,

So for 12000 gm of fat in camel hump 12000 * 0.491 moles of ATP will be produced .

= 5892 moles

Therefore Answer is 5892 moles .

If Hydrolysis of ATP releases 7.3 kcal/mole

so 5892 moles will produce 5892 * 7.3 kcal  

=43012 kcal energy will be generated by the utilization of the fat.

To know more about triacyclglycerols

https://brainly.com/question/13020914

#SPJ1

ACCESS MORE