This is hard to show but here is how you would determine these. NOTE each dot is an electron.
Question 1)
F-H
1) determine the valance electrons for each. F has 7 and H has 1
2) one electron from both F and H form the bond "-" which means that you still have 6 electrons to place around F and none to place around H. Place the 6 in sets of 2 around the F
..
F-H
¨
Question 2)
2) H-O-H
H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place
H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place
O has 6 valence electrons minus 2 used in the bonds to the H's = 4 electrons to place
H-O-H: place two dots above and below the oxygen
Question 3)
3) O=N----H : NOTE: a double bond requires O and N to share two of their electrons each
O has 6 valence electrons minus 2 used in the bonds to N = 4 electrons to place
N has 5 valence electrons minus 3 used in the bonds to O and H = 2 electrons to place
H has 1 valence electron minus 1 used in the bond to N = 0 electrons to place
place the 2 dots on top and bottom of oxygen.
place 2 above the N