Question

What volume is occupied by 2.1 g O2 at 13 C and a pressure of 0.1atm?

Answer 1

PV=nRT

n = mole = 2.1 g : 32 g/mole = 0.065

T = 13 + 273 = 286 K

V = nRT/P

V = (0.065 x 0.08205 x  286)/0.1

V = 15.253 L