Quadratic equation has a leading degrees of 2. The correct equation in vertex form is (x - 3)^2 + 5
Vertex form of a quadratic equation
Quadratic equation has a leading degrees of 2.
Given the quadratic function expressed as:
f(x) = x^2 - 6x + 14
Complete the square
x^2 - 6x + (-3)^2 - (-3)^2 + 14
(x- 3)^2 - 9 + 14
(x - 3)^2 + 5
Hence the correct equation in vertex form is (x - 3)^2 + 5
Learn more on vertex form here: https://brainly.com/question/525947
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