The linear equation is y = (2/3)*x - 5, and the 4 points in the graph are:
{ (-1, -17/3), (0, -5), (1, -13/3), (2, -11/3)}
How to identify the points on the line?
A linear equation written in the slope-intercept form is:
y = a*x + b
Where a is the slope and b is the y-intercept.
In this case, we have:
a = 2/3
b = -5
So our line is:
y = (2/3)*x - 5
To find the points, we need to evaluate the line in 4 different values of x.
We will use: x = -1, 0, 1, 2.
for x = -1 we have:
y = (2/3)*-1 - 5 = -2/3 - 5 = -17/3
So this gives the point (-1, -17/3).
for x = 0 we have:
y = (2/3)*0 - 5 = -5
So this gives the point (0, -5).
for x = 1 we have:
y = (2/3)*1 - 5 = -13/3
So this gives the point (1, -13/3).
for x = 2 we have:
y = (2/3)*2 - 5 = 4/3 - 15/3 = -11/3
So this gives the point (2, -11/3).
Then the 4 points are:
{ (-1, -17/3), (0, -5), (1, -13/3), (2, -11/3)}
If you want to learn more about linear equations:
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