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Use the t-distribution to find a confidence interval for a difference in means μ1−μ2 given the relevant sample results. Give the best estimate for μ1−μ2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed.

A 99% confidence interval for μ1−μ2 using the sample results x⎯⎯1=535, s1=103, n1=380 and x⎯⎯2=465, s2=86, n2=200

Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places.

Respuesta :

The best estimate and the degree of freedom when the t-distribution is used to find a confidence interval is 7 and 56 respectively.

How to illustrate the research?

The best estimate from the information given in the research will be:

= X1 - X2

= 53.5 - 46.5

= 7

The degree of freedom will be:

= 38 + 20 - 2

= 56

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