Amir drove from Jerusalem to the lowest place on Earth, the Dead Sea. His altitude relative to sea level (in meters) as a function of time (in minutes) is graphed. How fast did Amir descend?
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The equation for the flowing rate of aamir is as follows y = -12x +360
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
First of all let's write the slope-intercept form of the equation of a line, which is:
y = mx + c
So we just need to find to solve this problem.
Moreover, this problem tells us that Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. So this rate is the slope of the line, that is:
Negative slope because Amir is descending. So:
y = - 12x + b
To find, we need to use the information that tells us that he was at sea level after 30 minutes of driving, so this can be written as the point. Therefore, substituting this point into our equation:
y = -12x + b
0 = -12(30) + b
b = 360
Finally, the equation of Amir's altitude relative to sea level (in meters) and time (in minutes) is:
y = -12x +360
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