Question

Find the equation of the straight line with the gradient -2/3 and passing through the point(1,1)

Answer 1

Answer:

y = -2/3 x + 5/3

Step-by-step explanation:

y = mx + b

y = -2/3 x + b

1 = -2/3 × 1 + b

3/3 + 2/3 = b

b = 5/3

y = -2/3 x + 5/3