The maximum value of the objective function p if p = 180x + 250y is 3020
How to determine the maximum value?
The coordinates of the feasible region are given as;
(14, 2), (0, 9), (6, 8), and (10, 3)
The objective function is given as:
P = 180x + 250y
Substitute the coordinates of the feasible region in the above function
P = 180 * 14 + 250 * 2 =3020
P = 180 * 0 + 250 * 9 = 2250
P = 180 * 6 + 250 * 8 = 3080
P = 180 * 10 + 250 * 3 = 2550
The maximum value in the above computation is:
P = 180 * 14 + 250 * 2 =3020
Hence, the maximum value of the objective function p if p = 180x + 250y is 3020
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