Question

How many different orders of top-three finishers are possible?
Drag the tiles to the correct locations on the equation. Not all tiles will be used.

Answer 1

Using the permutation formula, it is found that the number of different orders of top-three finishers that are possible is given as follows:

$nPr = \frac{14!}{11!} = 2184$.

The order in which the cars finish is important, hence the permutation formula is used instead of the combination formula.

What is the permutation formula?

The number of possible permutations of x elements from a set of n elements is given by:

$nPr = \frac{n!}{(n-r)!}$

In this problem, 3 cars are taken from a set of 14, hence the number of different orders is given as follows:

$nPr = \frac{14!}{11!} = 2184$.

More can be learned about the permutation formula at https://brainly.com/question/25925367

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