Question

In the parallelogram shown, ae = p − 8, ce = 2p − 58, and de = p 15. parallelogram a b c d is shown. diagonals are drawn from point a to point c and from point d to point b and intersect at point e. what is the length of line segment eb? 42 units 50 units 65 units 73 units

Answer 1

If diagonals are drawn from point a to point c . The length of line segment eb is 65 units.

Length of line segment

Since the diagonal of  parallelogram bisect one another, hence:

AE=CE

EB=DE=P+15

P-8=2P-58

P=50

Hence:

EB=P+15

EB=50+15

EB=65 units

Therefore the length of line segment eb is 65 units.

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