Question

Consider an isosceles trapezoid rotated about an axis of symmetry that passes through the midpoint of the bases. the minor base of the trapezoid is 10 cm and the major base is 13 cm. what is the perimeter of the horizontal cross section if the cut is made at the middle of the height of the trapezoid?

Answer 1

Based on the calculation, the perimeter of the horizontal cross-section is equal to 36.13 cm.

How to calculate the perimeter?

In this scenario, the resulting geometrical shape formed when the cut is made at the middle of the height of the trapezoid and then rotated is a circle.

Given the following data:

• Minor base = 10 cm.

• Major base = 13 cm.

From the middle, the diameter of this circle is given by:

D = 1/2 (10 + 13)

D = 11.5 cm.

Now, we can calculate the perimeter:

Perimeter = πD

Perimeter = 3.142 × 11.5

Perimeter = 36.13 cm.

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