Answer:
[tex]x=3.18[/tex] [tex]cm[/tex]
Explanation:
[tex]x=3.18[/tex] [tex]cm[/tex]
Substitute [tex]y=6 cm[/tex] into [tex]\frac{}{AC} =y:\frac{}{AC} =6cm[/tex]
Substitute [tex]0=32[/tex] into ∠[tex]CAB=0:[/tex] ∠[tex]CAB=32^o[/tex]
sinA=leg opposite ∠A/hypotenuse : [tex]sin(CAB)=\frac{\frac{}{BC} }{\frac{}{AC} }[/tex]
Substitute [tex]\frac{}{BC} =x,\frac{}{AC}=6cm,[/tex] ∠[tex]CAB=32^o[/tex]
into sin(∠[tex]CAB[/tex]) [tex]=\frac{\frac{}{BC} }{\frac{}{AC} }:sin(32^o)=\frac{x}{6}[/tex]
Calculate [tex]sin(32^o)=\frac{x}{6} :x=3.18cm[/tex]
