Question

Find the sum of the first 8 terms of the following series, to the nearest integer 48,60,75

Answer 1

The series is a geometric series and the sum of the first 8 terms of the series 48, 60, 75 is 952.32

How to determine the sum of the first 8 terms?

The series is given as:

48, 60, 75

The above series is a geometric series with the following parameters:

First term, a = 48

Common ratio, r = 1.25

The sum of n terms is:

$S_n = \frac{a(r^n - 1)}{r -1}$

So, we have:

$S_8 = \frac{48 * (1.25^8 - 1)}{1.25 -1}$

Evaluate

$S_8 = 952.32$

Hence, the sum of the first 8 terms of the series is 952.32

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