Answer:
ABC is not a right angled triangle.
Step-by-step explanation:
Step 1: Given the perimeter of ΔABC = 22 cm, sides AB = 8 cm and BC = 5 cm. Find the side AC.
Perimeter = AB + BC + AC
⇒ AC = 22 - (8 + 5) = 22 - 13 = 9 cm
Step 2: Find whether the triangle is right angled using Pythagoras Theorem which is Hypotenuse² = Side² + Base²
AC² = AB² + BC²
⇒ AC² = 9² = 81
⇒ AB² + BC² = 8² + 5² = 64 + 25 = 89
∴ AC² ≠ AB² + BC²
⇒ ΔABC is not a right angled triangle.
