Question

How many moles of solute are in 125 mL of a 2.0 M hydrochloric acid (HCI) solution?
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Answer 1

$\sf\large \green{\underbrace{\red{Answer⋆}}}:$

0.250 moles

Explanation:

First we will convert quantity of solution into liters

$\implies \sf 125 \: ml \times {10}^{ - 3} = 0.125 \: l$

Now we will use morality formula

$\sf molarity = \frac{no \: of \: moles}{volume} \\ \\ \sf no \: of \: moles = molarity \times volume$

Here volume(quantity) = 0.125 l

AND no. of moles(given) = 2.0M

$\sf \implies no \: of \: moles = 2 \times 0.125 \\ \\ \sf \implies no \: of \: moles = 0.250 \: moles \: of \: HCl$

Answer 2

$~~~~~~w = \dfrac{SVM}{1000}\\\\\\\implies nM = \dfrac{SVM}{1000}\\\\\\\implies n= \dfrac{SV}{1000}\\\\\\\implies n = \dfrac{125 ~ \text{mL}\times 2.0~ \text{M}}{1000}\\\\\\\implies n = \dfrac{250}{1000}\\\\\\\implies n = 0.25~ \text{mol.}\\\\\text{The number of moles is 0.25.}$