Can someone please help me?
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The center of the circle will be equal to (-3,4) equation of the circle x²+y²+6x-8y+16=4
The circle is defined as the locus of the point traces around a fixed point called as the center and is equidistant from the out trace.
The general form of the equation of the circle is:-
(x-x₁)²+(y-y₁)²=r²
here x1 and y1 are the center of the circle
Now we will convert our equation in the general form:-
x²+y²+6x-8y+16=4
x²+6xy²-8y+16-4=0
x²+3x+3x+9-9+y²-4y-4y+16-16-4=0
(x+3)²+(y-4)²-9-16+16-4=0 (x+3)²+(y-4)²=13
By comparing with the general form we can see that the coordinate of the center of the circle will be {-3,4)
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