[tex]W + \frac{1}{4} = \frac{5}{6} [/tex]
Solving:
least common multiple (4,6)
4,6| 2
2,3| 2
1,3| 3
1,1|------- 2*2*3 = 12
LCM of 4 and 6, it is 12
Now, we have:
[tex]W + \frac{1}{4} = \frac{5}{6} [/tex]
[tex] \frac{12W}{12}+ \frac{3}{12} = \frac{10}{12} [/tex]
cancel denominators
[tex]\frac{12W}{\diagup\!\!\!\!\!12}+ \frac{3}{\diagup\!\!\!\!\!12} = \frac{10}{\diagup\!\!\!\!\!12} [/tex]
[tex]12W + 3 = 10[/tex]
Keep the number with the incognito on the left and swap the number without incident to the right, changing its signal.
[tex]12W = 10 - 3
[/tex]
[tex]12W = 7[/tex]
[tex]\boxed{\boxed{W = \frac{7}{12}}}[/tex]
Answer:
[tex]\boxed{\boxed{W = \frac{7}{12}}}[/tex] [tex]\end{array}}\qquad\quad\checkmark[/tex]
