Byron is 3 years older than Doug b=d+3.........(1) The product of their age is 40 bd=40...........(2) Substitute the value of b from (1) to (2) (d+3)d=40 d^2+3d=40 d^2+3d-40=0 Now solve for d d^2+8d-5d-40=0 d(d+8)-5(d+8)=0 (d-5)(d+8)=0 d-5=0 or d+8=0 d=5 or d=-8 d=-8 (inadmissible) So d=5 Put the value of d in (1) b=d+3.........(1) b=5+3 b=8
Present age of Byron = b = 8 years old Present age of Doug = d = 5 years old
