Answer:
5.39 units.
Step-by-step explanation:
We have been given an image of two squares on coordinate plane. We are asked to find the length of B'B.
We will use distance formula to solve our given problem.
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Let point [tex](0,2)=(x_1,y_1)[/tex] and [tex](5,4)=(x_2,y_2)[/tex].
Upon substituting coordinates of our given points in distance formula, we will get:
[tex]d=\sqrt{(5-0)^2+(4-2)^2}[/tex]
[tex]d=\sqrt{(5)^2+(2)^2}[/tex]
[tex]d=\sqrt{25+4}[/tex]
[tex]d=\sqrt{29}[/tex]
[tex]d=5.3851\approx 5.39[/tex]
Therefore, the length of B'B is approximately 5.39 units.