Respuesta :
The relation between hydroxide ion (OH-) and hydronium ion (H3O+) is given by:
pH + pOH = 14, which is equivalent to [H3O+] [OH-] = 10^ -14
=> [H3O+] = (10^ -14) / [OH-] = (10^ -14) / (1.4*10^-10) = 0.71 * 10^ - 4 = 0.071 * 10^-5
Answer: 0.071 * 10 ^ -5
pH + pOH = 14, which is equivalent to [H3O+] [OH-] = 10^ -14
=> [H3O+] = (10^ -14) / [OH-] = (10^ -14) / (1.4*10^-10) = 0.71 * 10^ - 4 = 0.071 * 10^-5
Answer: 0.071 * 10 ^ -5