Question

Take -4 + 3a^2 from 7a - a^2.

Answer 1

hint:  $\bf (7a-a^2)-(-4 + 3a^2)\implies 7a - a^2+4-3a^2 \\ \quad \\ 7a \boxed{-3a^2- a^2}+4\impliedby \textit{add like-terms}$

Answer 2

Answer:

$-4a^2+7a+4$

Step-by-step explanation:

We are asked to take $-4+3a^2$ from $7a-a^2$.

Taking $-4+3a^2$ from $7a-a^2$ means subtracting $-4+3a^2$ from $7a-a^2$ as:

$7a-a^2-(-4+3a^2)$

Use distributive property:

$7a-a^2+4-3a^2$

Combine like terms:

$-3a^2-a^2+7a+4$

$-4a^2+7a+4$

Therefore, our required expression would be $-4a^2+7a+4$.