Respuesta :
[tex] \frac{cos(a-b)}{cos(a)cos(b)} = \frac{cos(a)cos(b)+sin(a)sin(b)}{cos(a)cos(b)} = 1+ \frac{sin(a)sin(b)}{cos(a)cos(b)} =1+tan(a)tan(b)[/tex]
Note that I used these identities :[tex]cos(a-b)=cos(a)cos(b)+sin(a)sin(b)[/tex] and [tex]tan(a)= \frac{sin(a)}{cos(a)} [/tex]
Note that I used these identities :[tex]cos(a-b)=cos(a)cos(b)+sin(a)sin(b)[/tex] and [tex]tan(a)= \frac{sin(a)}{cos(a)} [/tex]