Respuesta :
Answer:
csc angle C equals 3 over 2
Step-by-step explanation:
In this problem
The hypotenuse is BC (greater side)
The legs are AC and AB
we know that
[tex]csc(C) =\frac{1}{sin(C)}[/tex]
[tex]sin(C)=\frac{AB}{BC}[/tex] ----> opposite side of angle C divided by the hypotenuse
therefore
[tex]csc(C)=\frac{BC}{AB}[/tex]
substitute the given values
[tex]csc(C)=\frac{6}{4}[/tex]
Simplify
[tex]csc(C)=\frac{3}{2}[/tex]
Note In this problem, the ABC triangle cannot be a right triangle, since its measurements do not satisfy the Pythagoras theorem, so I assume that it must be a problem created for didactic purposes