1 Factor completely.
p2+7p+10 = (p + 5)(p + 2)
2 Factor completely.
x2+10x+16 = (x + 4)(x + 6)
3 Factor completely.
x2+7x−18 = (x + 9)(x - 2)
4 Factor completely.
x2−5x−24 = (x - 8)(x + 3)
5 Factor completely.
x2−3x−40 = (x - 8)(x + 5)
Answer:
(1)The factor of p²+ 7p + 10 are (p+5)(p+2) .
(2)The factor of x² + 10x + 16 are (x + 8)(x + 2) .
(3)The factors of x²+7x−18 are (x-2)(x+9) .
(4) The factors of x² -5x - 24 are( x+3)(x-8).
(5) The factors of x²− 3x − 40 are (x-8)(x+5).
Step-by-step explanation:
(1) As given the expression.
= p²+ 7p + 10
= p² + 5p + 2p + 10
= p (p+5)+2(p+5)
= (p+5)(p+2)
Therefore the factor of p²+ 7p + 10 are (p+5)(p+2) .
(2) As given the expression
= x² + 10x + 16
= x² + 8x + 2x + 16
= x (x + 8)+2 (x + 8)
= (x + 8)(x + 2)
Therefore the factor of x² + 10x + 16 are (x + 8)(x + 2) .
(3)As given the expression
= x² + 7x − 18
= x² +9x -2x -18
=x (x+9)-2 (x +9)
= (x-2)(x+9)
Therefore the factors of x²+7x−18 are (x-2)(x+9) .
(4)As given the expression
= x² -5x - 24
= x²-8x +3x -24
= x (x-8)+3(x-8)
= (x+3)(x-8)
Therefore the factors of x² -5x - 24 are( x+3)(x-8).
(5) As the expression given
= x²− 3x − 40
= x² -8x + 5x - 40
= x(x-8)+ 5(x-8)
=(x-8)(x+5)
Therefore the factors of x²− 3x − 40 are (x-8)(x+5).
