Question

What are the real zeros of the function g(x) = x³ + 2xÆ – x – 2?

Answer 1

g ( x ) = x³ + 2 x² - x - 2 
x³ + 2 x² - x - 2 = 0
x² ( x + 2 ) - ( x + 2 ) = 0
( x + 2 ) ( x² - 1 ) = 0
( x + 2 ) ( x + 1 ) ( x - 1 ) = 0
Answer:
The real zeroes are: x 1 = - 2 ,  x 2 = - 1 ,  x 3 = 1