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Rank the magnitudes of the force between the pairs from largest to smallest.

Rank the magnitudes of the force between the pairs from largest to smallest class=

Respuesta :

brekv

Answer:

a b c

Explanation:

I did this question

Magnitude of force from  largest to smallest rank :

A > B > C

What is coulomb's law  ?

According to Coulomb's law, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

According to Coulomb's law : k q1 q2 / [tex]r^{2}[/tex]

where k = 1/4π∈o = 9 * [tex]10^{9}[/tex] N[tex]m^{2}[/tex]/ [tex]C^{2}[/tex]

q1 = value of one charge

q2 = value of another charge

r = distance between both the charges

A) k (-1q)(+36q)/[tex](2x)^{2}[/tex] = - 36 k([tex]q^{2}[/tex]) / 4[tex]x^{2}[/tex] = -9 k([tex]q^{2}[/tex]) / [tex]x^{2}[/tex]

B) k (4q) (8q) /   [tex](2x)^{2}[/tex] = 32 k ([tex]q^{2}[/tex]) / 4[tex]x^{2}[/tex]   = 8 k([tex]q^{2}[/tex]) / [tex]x^{2}[/tex]

C) k (2q)(-2q) / [tex]x^{2}[/tex] = - 4 k  ([tex]q^{2}[/tex])  /  [tex]x^{2}[/tex]       = - 4 k  ([tex]q^{2}[/tex])  /  [tex]x^{2}[/tex]  

Magnitude of force from  largest to smallest rank :

A > B > C

learn more about  Coulomb's law :

https://brainly.com/question/14110379?referrer=searchResults

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