To Find:-
Grams Present in 3.45 Moles of Carbon.
We Know:-
Molecular Mass of Carbon Dioxide= 44.01 grams/mol or 44 grams/mol
[tex] \text{Moles} = \frac{\text{Mass}}{\text{Molecular mass}}[/tex]
[tex] \implies 3.45 \text{moles} = \frac{ \text{Mass}}{44 \text{g/mol}} \\ \\ \implies \text{Mass} = {44 \text{g/mol}} \times 3.45 \text{moles} \\ \\ \implies \text{Mass} = {44 \text{g/} \cancel\text{ mol}} \times 3.45 \cancel\text{moles} \\ \\ \implies \text{Mass} = 44 \text{g} \times 3.45 \\ \\ \implies \text{Mass} = \red{151.8 \text{g}}[/tex]
[tex]\therefore \text{Mass of 3.45 Moles of Carbon Dioxide is = \red{151.8g}}[/tex]