Question

using the height function H=-16t^2+1450, determine the average rate of change of H with the respect to t over the given interval

a. 0<t<1 b 1< t<2

Answer 1

just find the slope between those points 


0<t<1
t=0 and t=1

H(0)=1450
H(1)=1434
slope=(1434-1450)/(1-0)=(-16/1)=-16




1<t<2
t=1 and t=2
H(1)=1434
H(2)=1386
slope=(1386-1434)/(2-1)=-48/1=-48



in 0<t<1, average rate of change is -16
in 1<t<2, average rate of change is -48