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31-01-2017
Chemistry

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9. How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°C to 50.0°C? The specific heat of water is 4.184 J/(g•°C).

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togunsile2008 togunsile2008

31-01-2017

Heat = mass * specific heat * change in temperature

Heat = 15.5 * 4.184 * (50 - 20)

Heat = 15.5 * 4.184 * 30 ==== 1946J

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