Question

6. Find the surface area of the regular pyramid shown to the nearest whole number. The figure is not drawn to scale.

1,540 m2
770 m2
396 m2
749 m2

Answer 1

The surface area of the regular pyramid is 770 $m^{2}$

Option B. 770  $m^{2}$ is the answer.

What is Surface Area ?

The surface area of a pyramid is a measure of the total area that is occupied by all its faces.

We have to find the surface area of the regular pyramid with a base of 6 sides (hexagonal base).

Surface area of pyramid = area of triangles at the lateral sides + area of base (Hexagon)

Surface area of hexagonal base,

$\frac{1}{2}*(Apothem)*(Perimeter) \\= \frac{1}{2}*(6\sqrt{3} )*(72)\\=216\sqrt{3}$

Surface area of triangular sides = 6 * 1/2 * b *h

                                                       = 3 * 12 *11

                                                       = 396  $m^{2}$

Now total surface area = 216√3 + 396

                                        = 374.112 + 396

                                        = 770.112

                                        ≈ 770 $m^{2}$

The surface area of the regular pyramid is 770 $m^{2}$

Option B.  770 $m^{2}$

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