Question

PLSS HELP. ALGEBRA 1. 9TH GRADE..ASAP PLSSS

Answer 1

Answer:

y = - 4

Step-by-step explanation:

$\cfrac{2}{5}\left(10y-5\right)-2y=-10$ (Multiply)

$\cfrac{2\left(10y-5\right)}{5}-2y=-10$

$\cfrac{2\left(10y-5\right)}{5}\times \:5-2y\times \:5=-10\times \:5$

$2\left(10y-5\right)-10y=-50$ (Expand)

$10y-10=-50$

$10y-10+10=-50+10$ ( Add 10)

$10y=-40$ (Simplify)

$\cfrac{10y}{10}=\cfrac{-40}{10}$ (Divide by 10)

$y=-4$

Answer 2

Answer:

$y=-4$

Step-by-step explanation:

Given equation:

$\dfrac{2}{5}(10y-5)-2y=-10$

Expand the brackets:

$\implies \dfrac{2}{5}(10y)-\dfrac{2}{5}(5)-2y=-10$

$\implies \dfrac{2 \cdot 10}{5}y-\dfrac{2 \cdot 5}{5}-2y=-10$

$\implies \dfrac{20}{5}y-\dfrac{10}{5}-2y=-10$

$\implies 4y-2-2y=-10$

Collect like terms:

$\implies 4y-2y-2=-10$

Combine like terms:

$\implies 2y-2=-10$

Add 2 to both sides:

$\implies 2y-2+2=-10+2$

$\implies 2y=-8$

Divide both sides by 2:

$\implies \dfrac{2y}{2}=\dfrac{-8}{2}$

$\implies y=-4$