Shunt motors are direct current motors that have parallel windings with identical voltage. The total input power of the shunt motor is 25.724 kW and the line current will be 111.843 A.
Total input power is the ratio of the output power and the efficiency, while the line current is the proportion of input power to an input voltage.
The total input power (total IP) is calculated as:
Given,
Output power (OP) = 30 hp
Efficiency = 0.87
Substituting values:
[tex]\begin{aligned}\text{Total IP} &= \rm \dfrac {OP}{efficiency}\\\\&= \dfrac {30 \times 746 \rm \;watts}{0.87}\\\\&= 25.724 \;\rm kW \end {aligned}[/tex]
Line current is calculated as:
Given,
Input power (IP) = 25.724 kW
Input voltage (IV) = 230 Volt
Solving for line current:
[tex]\begin{aligned} \text{Line current} &= \rm \dfrac{IP}{IV}\\\\&= \dfrac{25.724 \times 10^{3}}{230}\\\\&= 111.843 \;\rm A \end{aligned}[/tex]
Therefore, the total input power of the shunt is 25.724 kW, and the line current is 111.843 A.
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