The resultant moles of nitrogen gas that are present in the container is 2.96 moles.
Mass of any substance will be converted into moles by using the below equation as:
n = W/M, where
From the ideal gas equation of gas we know that moles and volume is directly proportional to each other and for this question equation becomes,
V₁/n₁ = V₂/n₂, where
On putting all values, we get
n₂ = (5L)(1.78mol) / (3L) = 2.96 moles
Hence required moles of nitrogen gas are 2.96.
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