A NaCl solution of 350 mL volume and a concentration of 0.277 M will contain 5.67 grams of the salt.
Recall that:
Mole = molarity x volume.
Also:
Mass = mole x molar mass
Hence;
Mole of 350 mL, 0.277 NaCl = 0.350 x 0.277 = 0.097 moles
Mass of 0.097 moles NaCl = 0.097 x 58.44 = 5.67 grams
Thus, a 350 mL, 0.277 M NaCl solution will contain 5.67 grams of the salt.
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