The required elemental gas which has a mass of 10.3 g in the given conditions is helium gas.
Relation between the molar mass and moles of any substance will be represented as:
n = W/M, where
Moles of gas will be calculated by using the ideal gas equation:
PV = nRT, where
On putting all values, we get moles
n = (758)(58.4) / (62.363)(298) = 44,267.2 / 18,584.2
n = 2.38 moles
Molar mass of the gas will be calculated by using the above first equation is:
M = 10.3g / 2.38mol = 4.32 g/mol = 4g/mol (approx)
Hence given elemental gas is helium.
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