The amount of chalcopyrite must be mined to obtain 500g of pure Cu is 1.4 kilograms.
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
Moles of Cu = 500g / 63.5g/mol = 7.87 mole
Given chemical reaction is:
CuFeS₂ → Cu²⁺ + Fe²⁺ + 2S²⁻
From the stoichiometry of the reaction, it is clear that
1 mole of Cu = produced by 1 mole of CuFeS₂
7.87 mole of Cu = produced by 7.87 mole of CuFeS₂
Mass of given moles of CuFeS₂ = (7.87mol)(183.5g/mol) = 1,444.14g = 1.4kg
Hence required mass of CuFeS₂ is 1.4 kg.
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