Question

A 28. 0 ml sample of vinegar, which is an aqueous solution of acetic acid, ch3cooh, requires 21. 5 ml of 0. 550 m naoh to reach the endpoint in a titration

Answer 1

Concentration of vinegar sample of 28mL which requires 21. 5 ml of 0.550 M NaOH to reach the endpoint in a titration is 0.42M.

How do we calculate the concentration of Vinegar?

Concentration of vinegar in the titration method will be used by using the below equation:

M₁V₁ = M₂V₂,

• M₁ & V₁ are the molarity and volume of acetic acid.
• M₂ & V₂ are the molarity and volume of vinegar sample.

By putting values on above equation from the question, we get

M₂ = (0.55M)(21.5mL) / (28mL) = 0.42 M

Hence, required concentration of vinegar is 0.42M.

To know more about concentration, visit the below link:

https://brainly.com/question/14469428

#SPJ4