The amount in grams of oxygen are needed to react with 25g of Mg is 16.48 grams.
Mass into moles or vice versa of any substance will be calculated by using the below formula as:
n = W/M, where
W = given mass
M = molar mass
Moles of Magnesium = 25g / 24.3g/mol = 1.028 = 1.03 mol
Chemical reaction will be:
2Mg + O₂ → 2MgO
From the stoichiometry of the reaction it is clear that 1 mole of oxygen is reacts with 2 moles of magnesium, so 1.03 moles of magnesium will reacts with (1/2)(1.03) = 0.515 moles of oxygen.
Mass of oxygen = (0.515mol)(32g/mol) = 16.48g
Hence required mass of oxygen is 16.48 grams.
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