The pressure (in atm) in a 5 L tank with 37.50 grams of oxygen gas at 350 K is 6.715 atm.
Pressure of gas will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure = ?
V = volume = 5 L
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 350 K
n is the moles of gas and it will be calculated as:
n = W/M, where
W = given mass = 37.50 g
M = molar mass of oxygen = 32g/mol
n = 37.50/32 = 1.17 mol
On putting all these values, we get
P = (1.17)(0.082)(350) / (5) = 6.715 atm
Hence resultant pressure of the oxygen gas is 6.715 atm.
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