The value of concentration of H₃O⁺ of the polyprotic acid solution 0.140M H₃C₆H₅O₇ is 2.1×10⁻⁴M.
Ka is the acid dissociation constant which shows its value in the equilibrium condition.
Given chemical reaction with ICE table is:
H₃C₆H₅O₇ → C₆H₅O₆⁻ + H₃O⁺
Initial: 0.140 0 0
Change: -x +x +x
Equilibrium: 0.140-x x x
Ka for the acid = (x)(x) / (0.140-x)
For the H₃C₆H₅O₇ acid value of Ka = 3.2 × 10⁻⁷
We can neglect the value of x from the term 0.140-x, as x is vey small as compared to 0.140 so that equation becomes,
3.2 × 10⁻⁷ = x² / 0.140
x = 2.1×10⁻⁴M
Hence the concentration of H₃O⁺ is 2.1×10⁻⁴M.
To know more about Ka, visit the below link:
https://brainly.com/question/3006391
#SPJ4
