Question

How many grams of pbcl2 will be formed from 50. 0ml of a 1. 50m kcl solution?

Answer 1

Mass is the multiplication product of moles and the molar mass. The mass of the lead chloride formed from 1.50 M potassium chloride is 10.42 gm.

What is molarity?

The molarity of the solution is the ratio of the moles to the volume of the solution.

The double displacement reaction is shown as,

$\rm 2KCl + Pb(NO_{3})_{2} \rightarrow PbCl_{2} + 2KNO_{3}$

From the reaction, it can be said that the stoichiometry ratio of potassium chloride and lead chloride is 2:1.

Given,

Molarity of potassium chloride = 1.50 M

1 L of potassium chloride = 1.50 moles

So, 50.0 ml will have,

$\dfrac{1.50 \times 50}{1000} = 0.075\;\rm moles$

Moles of lead chloride formed will be:

$\begin{aligned} &= \dfrac{1}{2} \times \text{number of KCl moles reacted}\\\\&= \dfrac{0.075}{2}\\\\&= 0.0375\;\rm moles\end{aligned}$

Given,

Moles of lead chloride = 0.0375 moles

Molar mass of lead chloride =  278 g/mol

Mass of lead chloride is calculated as:

$278 \times 0.0375 = 10.42 \;\rm gm$

Therefore, 10.42 gm of lead chloride is formed.

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