Question

A proton of energy 900gev collides with a stationary proton. Find the available energy ea. The rest energy of the proton is 938mev

Answer 1

The total energy available during the collision of the two protons is determined as 900,938 MeV.

Total energy available during the collision

Based on the principle of conservation of energy, the total energy of the two protons during the collision will be conserved.

Available energy = Er + K

Where;

• Er is the rest energy
• K is the kinetic energy

Available energy = 938 MeV + 900 GeV

Available energy = 938 Mev + 900 x 10³ MeV

Available energy = 938 MeV + 900,000 MeV

Available energy = 900,938 MeV

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