Question

What is the temperature (in °C) if 12.1 g of N2 in a 1.3 L container has a pressure of 5.8 atm?

Answer 1

Answer:

T=-166.8 C

Explanation:

PM=m/vRT

T=PMV/mR

T=5.8*14*1.3/12.1*0.08206

T=106.3K

=106-273.15=-166.8 C