If the height of the frustum of the cone is 10 cm. Then the volume of this cup will be 47 milliliters.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
A small plastic vessel has the shape of a truncated cone as shown. A cubic centimeter is the same as a milliliter.
Then the volume of this cup to the nearest milliliter will be
The volume is given as
[tex]\rm V = \dfrac{1}{3} \pi (r_2^2 - r_1^2) h[/tex]
We have
Height (h) = 10 cm = 0.1 m
Radius (r₁) = 3.2 cm = 0.032 m
Radius (r₂) = 2.4 cm = 0.024 m
Then the volume will be
[tex]\rm V = \dfrac{1}{3} \pi (0.032^2 - 0.024^2) \times 0.1\\\\\rm V = 4.7 \times 10^{-5} \ \ m^3[/tex]
Then the conversion of m³ to milliliters will be
4.7 × 10⁻⁵ m³ = 4.7 × 10⁻⁵ × 10⁶ millileters
4.7 × 10⁻⁵ m³ = 47 milliliters
More about the geometry link is given below.
https://brainly.com/question/7558603
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