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Suppose a rocket is launched from a platform. The function h(t) - 4.96 + 200€ + 25gives the rocket's
height, h, in meters, in terms of time, t, in seconds. The function h(t) is equivalent to -4.9(t- 20. 41) + 2,065.82

Suppose a rocket is launched from a platform The function ht 496 200 25gives the rockets height h in meters in terms of time t in seconds The function ht is equ class=

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Answer:

See below

Step-by-step explanation:

Opens Downward   ( due to the  -  coefficient  of t^2 )

when t = 0    the height is = 25 meters

initial velocity = 200 m/s

Vertex = 20.41, 2065.82

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